...Physics?
The question asks me to calculate the initial speed of the popper. I did the lab (it was a real small mini lab, really fun) and I got the average max height of the popper. 106.5. I know the accleration is -9.8 m/s ^2 (Do I have to square it when doing the calculations?) And I know the final velocity is zero 0. So now what equation am I suppose to plug it into? Really confused!
Update:Thank you dearly, dancing_rox464. I'll try it tomorrow morning.
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(Vf)^2 = (Vo)^2 +2ad
(Final velocity) ^2 = (Original velocity)^2 + 2ad
a = accelleration
d=distance
If you have the time in seconds you can use
at = (Vf - Vo) That is a lot simpler.
Don't forget to make sure you have the units correct. Yes, acceleration is -9.8 m/s^2 in the equasion too. You should get your answer in m/s because that is what velocity is measured in.