If you start with ten grams of lithium hydroxide, how may grams of lithium bromide will be produced?
moles LiOH = 10 g / 23.947 g/mol=0.418
= moles LiBr
mass LiBr = 0.418 x 86.845 g/mol=36.3 g
Copyright © 2023 VQUIX.COM - All rights reserved.
Answers & Comments
Verified answer
moles LiOH = 10 g / 23.947 g/mol=0.418
= moles LiBr
mass LiBr = 0.418 x 86.845 g/mol=36.3 g