Verified answer

Jennifer is wrong. You need to use their "closing speed" which is the sum of their two speeds, or 140km/h.

t = D /r = 7.5/140 = 0.0535714h [3 minutes 12.8 seconds]

you need to use the speed=distance divided by time formula.

v=d/t

where v= 70 km/hr,

d= 7.5 km,

and solve for t (time).

nicely the respond is definite a fly can stop a speedy shifting practice, the result tottally relies upon on the determination of reference For egs, you're observer from moon initially fly exchange into flying interior the gap whilst the fly headed in the direction of the earth then the two the fly and the practice look shifting with the same velocity i.e. through earths rotation in this technique there exchange right into a metamorphosis in flyies action keep in mind whilst the fly exchange into scuffling with the practice then there exchange right into a sprint rigidity performing between them which follows newtons 0.33 regulation for this reason if the flies velocity greater whilst coming into earths physique as referred to from moon(observer) then there could be some significant volume of rigidity referred to utilized via the fly& it may look as though the fly has stopped practice (yet from moons reference physique)