Verified answer

Hi try this:

echo "<span class='text5\'>".$result[' definition']."</span><p>";

you have been putting a php "variable" within the print string.

You must separate all php variables from a string in "" like this:

<?php

$name = "john";

echo "My name is ".$name;

?>

and not like:

<?php

$name = "john";

echo "My name is $name";

?>

Php Print Class

1) $nav_bar = "<div id=nav> <a href=index.php><div class=<?php if($page == index.php){echo active}else{echo button}?>>Home</div></a> is all part of $nav_bar. You have to close the quote. $nav_bar = "<div id=nav> <a href=index.php><div class="; <?php if($page == index.php){echo active;}else{echo button;}?> $nav_bar .- ">Home</div></a> etc. 2) echo "$nav_bar" will echo the contents of $nav_bar (echo '$nav_bar' will echo the string $nav_bar) but it's a waste of processing power, since you aren't echoing any literals. echo $nav_bar will give you the same output without making the PHP parser figure out ewhat's inside the quotes. For a small site that gets a few hits, it makes very little difference. On a very busy site a few dozen uses of unneeded quotes could make the difference between the site working and the site crashing.

Instead of this :

echo "<span class=\"text5\">

$result[' definition']

</span><p>";

try this

echo "<span class=\"text5\">".

$result['definition'].

"</span><p>";

or better

<span class="text5">

<?php echo $result['definition'] ?>

</span>

avoid(as long as you can) writing HTML code with PHP, use it only for content