45 physics?
4. A drinking glass is a cylinder 20cm high and 8cm in diameter on the inside. It is filled halfway with water. What is the pressure at the bottom of the glass?
5. Several ice cubes are added to the glass. What happens to the pressure at the bottom? Explain why in terms of the variables in the formula for pressure in a liquid.
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1) The formula for determining the pressure exerted by water at a certain depth is:
p = Patm + dgh
where p = pressure at the depth h
Patm = pressure exerted by the atmosphere on the surface
of the water
d = density of water = 1000 kg/m^3
h = depth = 20 cm = 0.20 m
g = 9.8 m/s^2
Assume a normal atmospheric pressure of 1.01 x 10^5 N/m^2; hence,
Patm = 1.01 x 10^5 N/m^2
p = Patm + dgh
p = 1.01 x 10^5 N/m^2 + (1000kg/m^3)(9.8 m/s^2)(0.20m)
p = 102960 N/m^2 or 103,000 N/m^2 ANS
b) Ice has lesser density than liquid water but will nevertheless contribute to the weight exerted on the bottom of the glass. It will cause the level of water, h, to increase thus increasing the pressure at the bottom of the glass
teddy boy
4 ) Pressure = Density X gravity acceleration X height .
Density of water 1000 Kgm^-3
Gravity acceleration =9.8
Height = 8*10^-2 /2
Pressure = 1000X9.8X(8*10^-2 /2)
=392 Pa .
cc disp = Ï * r² * stroke
cc disp = Ï * 8² * 20
cc disp = Ï * 8² * 20
cc disp = Ï * 62 * 20
3895 cc = Ï *1240
3.895 L / 4.54 L = 0.858 * 10
8.58 LBS / 31.2 sq/in
0.275 LBS/IN² I think !