physicsssss?
A 63.5 kg pole vaulter running at 8.0 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar is 1.0 m/s and air resistance is disregarded, how high was the jump?
_____ m
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We find h = Uy^2/2g so we need to find Uy^2 = (U^2 - Ux^2). By substitution we have h = (U^2 - Ux^2)/2g = (64 - 1)/(2*9.81) = 3.21 meters ANS.