Physics ==..........?
If you have 0.411 m3 of water at 25.0°C and add 0.142 m3 of water at 95.0°C, what is the final temperature of the mixture? Use 1000 kg/m3 as the density of water at any temperature.
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I am not sure about this, but i think you do it like this. Convert t for celsius to kelvin. Multiply volume of one container by it's temperature(in kelvin) + volume of the other * temperature of the other. Divide all that by combined volume. (0.411*298+0.142*368)/0.553= 315.97K= 42.97 degrees C
use m1 c1 dt1 = m2 c2 dt2. m=density*vol, c is same dt1= T-25 dt2=95-T
solving we get T=42.97