If the average density of a human being is 980 kg/m3, what fraction of a human body floats above water in a freshwater pond and what fraction floats above seawater in the ocean? The specific gravity of seawater is 1.025.
Copyright © 2024 VQUIX.COM - All rights reserved.
Answers & Comments
Verified answer
Let the volume of human body is V m^3 & the submerged volume is V' m^3
=>For water:-
=>V'd(w)g = Vd(human)g
=>V'/V = d(h)/d(w)
=>V'/V = 980/1000 = 0.98
=>V' = 0.98V
=>Body floating above water = 1-0.98 = 0.02V
=>For sea water:-
=>V'/V = 980/1025
=>V' = 0.96V
=>Body floating above water = 1-0.96 = 0.04V