If a planet has a radius of 100km (don't forget to convert to meters) and a 10kg mass has a weight 70N, what's the mass of the planet?
Weight = mass * g
On the earth, g = 9.8 m/s^2
Weight = 10 * 9.8 = 98 N
Let’s determine the value of g on this planet.
70 = 10 * g, g = 7 m/s^2
The unit of g is m/s^2. This the unit for acceleration.
Now let me show you how g relates to the equation of the “Universal gravitational force of attraction”.
Fg = (G * M * m) ÷ d^2
And
Force = m * a
Set these 2 equations equal to each other.
(G * M * m) ÷ d^2 = m * a
Divide both sides by m
(G * M) ÷ d^2 = a
“a” is the acceleration. so g = a
This is the equation for g
(G * M) ÷ d^2 = g
G = 6.67 * 10^-11, M is the mass of the planet
d is the distance from the center of mass one to the center of mass of the other object.
In this problem, the 2 objects are a planet and a person. Since the person is on the surface of the planet, d is the radius of the planet.
On this planet g = 7 m/s^2 and r = 100 km = 1 * 10^5 meters
(6.67 * 10^-11 * M) ÷ (1 * 10^5)^2 = 7
Solve for M
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Verified answer
Weight = mass * g
On the earth, g = 9.8 m/s^2
Weight = 10 * 9.8 = 98 N
Let’s determine the value of g on this planet.
70 = 10 * g, g = 7 m/s^2
The unit of g is m/s^2. This the unit for acceleration.
Now let me show you how g relates to the equation of the “Universal gravitational force of attraction”.
Fg = (G * M * m) ÷ d^2
And
Force = m * a
Set these 2 equations equal to each other.
(G * M * m) ÷ d^2 = m * a
Divide both sides by m
(G * M) ÷ d^2 = a
“a” is the acceleration. so g = a
This is the equation for g
(G * M) ÷ d^2 = g
G = 6.67 * 10^-11, M is the mass of the planet
d is the distance from the center of mass one to the center of mass of the other object.
In this problem, the 2 objects are a planet and a person. Since the person is on the surface of the planet, d is the radius of the planet.
On this planet g = 7 m/s^2 and r = 100 km = 1 * 10^5 meters
(6.67 * 10^-11 * M) ÷ (1 * 10^5)^2 = 7
Solve for M