Physics Homework Trouble?
The question is:
A dragster slows down from 28m/s[N] to 13m/s[N] in a time of 12s using a parachute and brakes. Calculate the displacement during this accleleration.
I don't understand the equation for this question since it is acceleration
Can someone please explain to me how to do this??
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Verified answer
Use one of the kinematic equations of motion:
u = initial velocity = 28 m/s
v = final velocity = 13 m/s
t = time = 12 s
d = displacement = ?
"During this acceleration" only tells you that there is a change in speed involved, your equation does not have to have an acceleration in it.
In fact, the distance can be found directly via d = t(v+u)/2:
d = 12(28+13)/2 = 246 m.
So the distance is 246 m, to convert to a displacement you need to add in the direction , which is [N] for north: The displacement is 246 m [N].