Physics help - Velocity?
19.) Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in
an elastic collision. The yellow disk is initially at rest and is struck by the orange disk moving
initially to the right at 5.90 m/s. After the collision, the orange disk is at rest. What is the velocity of the yellow disk after the collision? Answer in units of m/s.
More Questions From This User See All
Answers & Comments
Verified answer
You really should do your homework on your own using your textbook. But:
Using conservation of momentum the velocity of the yellow disk should be the same as the initial velocity of the orange disk assuming that it is a perfectly elastic collision. m1iV1i^2+m2iV2i^2=m1fV1f^2+m2fV2f^2
Before collision m2=stationary, and after collision m1=stationary so:
m1iV1i^2=m2fV2f^2
m1=m2 so V1i^2=V2f^2 or V1i=V2f
EDIT: I guess the formula I gave is the conservation of energy formula and not conservation of linear momentum, but the result is the same and both work.
Basically the momentum is the same before and after the collision.
The disks are the same mass one is at rest before , the other is at rest after - so think about it - no calculation should be necessary - the yellow disk takes on the motion of the orange disk.
Wow, and nobody just answered? I mean, their explanations are correct, but they didn't actually give the answer. 5.90 m/s to the "right". Remember that velocity is speed with a direction.
t0: O--> Y
t1: OY
t2: O Y-->
I mean, if you really must calculate it:
[EnergyBefore] = [EnergyAfter]
[OrangeEB] + [YellowEB] = [OrangeEA] + [YellowEA]
{O}0.5mv^2 + {Y}0.5mv^2 = {O}0.5mv^2 + {Y}0.5mv^2
*Note that the masses are equal, so we can divide both sides by 0.5 and by m.
*Also remember that left side is before collision (t0) and right is after collision (t2).
{O}v^2 + {Y}v^2 = {O}v^2 + {Y}v^2
5.9^2 + 0^2 = 0^2 + ???^2
5.9^2 = ???^2
5.9 = ???
Ta-da!
Oh, and you really shouldn't use Yahoo Answers for homework... it's against the rules.
So i'm going to easily inform you the approach to fixing it : First you ought to calculate the entire displacement travelled, by making use of multiplying the cost to time then you definitely ought to sum up the entire time (upload jointly) ultimately, v = s/t = displacement / time So divide the entire displacement to procure with the entire time to procure it somewhat is conventional velocity P.S. do not ignore that velocity is a vector, so which you ought to provide the instructions ! (East)