MATH... travel time ?
If a plane can travel 460 miles per hour with the wind and 400 miles per hour against the wind, find the speed of the plane without a wind and the speed of the wind.
The speed of the plane in still air is __ miles per hour.
The speed of the wind is __ miles per hour.
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The speed S_a of the aircraft in still air is half the sum of the two speeds. That is,
S_a = (460 + 400)/2 = 430 mph
The speed S_w of the wind is half the difference of the two speeds. That is
S_w = (460 - 400)/2 = 30 mph
Of course the wind speed, could have been calculated from from subtracting s_a from 460
i rhink you find the difference and divide by two so 60/2 =30 so the spped of the plane =430 and the wind is 30 so when its with the wind its 460 and against =400
but im not sure
Let speed of plane in still air be x mph and speed of wind be y mph
WITH THE WIND
------------------------
Speed = ( x+y) = 460
AGAINST THE WIND
-------------------------------
Speed = ( x-y) = 400
JUST ADD THE 2 EQUATIONS
2x = 860
x = 430
y = 30
ANSWER speed of plane in still air = 430 mph and wind speed = 30 mph