Physics!!!?
A 14590 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force between the tires and the road is 7150 N. How far will the car slide once the brakes are applied? Air resistance negligible.
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w=mg
If the car is 14590N, then
14590N = m*9.8 m/s^2
So the mass of the car is 1488.78 kg.
If braking force is 7150N, then that force is the negative acceleration.
So with the equation F=ma, we need to find a, so we change it to a = F/m
a = 7250N/1488.78kg
a = -4.87 m/s^2
Then we need to use some distance equations.
distance = x
Vf = final velocity
Vi = initial velocity
x=(Vf^2 - Vi^2)/2a
Vf is zero, since it comes to a complete stop.
x = (-(25 m/s)^2) / 2*-4.87m/s^2
so x = 64.17 meters.
Does that help?