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A 245-kg crate is pushed horizontally with a force of 695 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.
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A 245-kg crate is pushed horizontally with a force of 695 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.
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Ffr= fn*u
= (245*9.8)(0.20)
= 480.2 N
Fnet=695N - 480.2N
=214.8N
Fnet=ma
a=F/m
= 214.8N/245kg
= 0.88 m/s^2
Use the following equation to determine the acceleration.
Net force = mass * acceleration
In this problem, the net force is the difference of the applied force and the friction force.
Ff = 0.2 * 245 * 9.8 = 480.2 N
Net force = 695 – 480.2 = 245 * a
a = 214.8 ÷ 245
This is approximately 0.877 m/s^2.