If Sammy the Stunt Cow is fired out of a cannon with a vertical velocity of 12.0 m/s and a horizontal velocity of 15.0 m/s, how fast was Sammy actually fired?
We are given Ux = U cos(theta) = 15 mps and Uy = U sin(theta) = 12 mps. So we have Uy/Ux = tan(theta) and theta = ATAN(Uy/Ux) = ATAN(.8) = 38.66265599 = 38.7 deg re the XX axis.
So we have U = Uy/sin(38.7) = 12/sin(radians(38.7)) = 19.19254849 = 19.2 mps @ theta = 38.7 deg re the XX when you need the vector. ANS.
The two vectors can be added tip to tail. They form a right angle triangle so we can use Pythagorus to find the resultant velocity (hypothenuse). I will assume you don't need to find the vector and that a scalar speed is sufficient.
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We are given Ux = U cos(theta) = 15 mps and Uy = U sin(theta) = 12 mps. So we have Uy/Ux = tan(theta) and theta = ATAN(Uy/Ux) = ATAN(.8) = 38.66265599 = 38.7 deg re the XX axis.
So we have U = Uy/sin(38.7) = 12/sin(radians(38.7)) = 19.19254849 = 19.2 mps @ theta = 38.7 deg re the XX when you need the vector. ANS.
The two vectors can be added tip to tail. They form a right angle triangle so we can use Pythagorus to find the resultant velocity (hypothenuse). I will assume you don't need to find the vector and that a scalar speed is sufficient.
Vres=â15.0^2+12.0^2
Vres=â369
Vres=19.2m/s