A 0.110-kg hockey puck, moving at 35.0 m/s, strikes a 0.255-kg jacket that is thrown onto the ice by a fan of a certain hockey team. The puck and jacket slide off together. Find their velocity. (Take the positive direction to be that of the initial direction of the puck.)
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m1 = mass of the puck = 0.110 kg
m2 = mass of the jacket = 0.255 kg
v1 = initial velocity of the puck = 35 m/s
v2 = velocity of the puck and the jacket after collision = ?
The system (puck and the jacket) will have the same momentum before and after the collision because no external force is acting on them.
=> m1v1 + m2(0) = m1v2 + m2v2
=> m1v1 = v2(m1 + m2)
=> v2 = m1v1 / (m1 + m2)
=> v2 = (0.110 x 35) / (0.110 + 0.255) = 10.548 m/s
try this www.physicssource.ca