Two charges are fixed in place on the x-axis as shown. The charge at x = 0 is negative and has magnitude q = 2 mCoulombs. The charge at x = d, (d = +12 cm), is positive and has magnitude Q = 4 mCoulombs. Find a point x = xo along the x-axis at which the electric field is zero.https://tycho-s.phys.washington.edu/cgi/courses/sh...Xo= ?cm. Created by mark. science-mathematics-en - physics-en

Edit***q1 = -2 * 10 ^ -3 'Cq2 = 4 * 10 ^ -3 'Ck = 9 * 10 ^ 912 centimeters = 0.12 metersE1 = k * q1 / (x) ^ 2E2 = k * q2 / (x+0.12) ^ 2solving for x:x = 0.12 / (Sqr(q2 / |q1|) - 1)x =0.2897 m "Left of origin"x = 28.97 cmcheck:E1 = -214466094 N/CE2 = 214466094 N/C∑E=0