A figure skater on ice with arms extended, spins at a rate of 2.0 revolutions per second. After she draws her arms in, she spins at 5.0 revolutions per second. By what factor has her moment of inertia changed in the process?
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compare rotational energy before and after. They should be equal
so:
I_1 * omega_1^2 / 2 = I_2 * omega_2 ^2 / 2
I_2/I_1 = (omega_1/omega_2)^2 =
(2/5)^2=0.16
Angular momentum will be conserved, so her (moment of inertia) times her (angular velocity squared) before will have to be equal to those measurements after. That means 4 times (2.0^2) her initial moment of inertia will have to equal 25 (5.0^2) times her final moment of inertia. This means her moment of inertia decreased TO a measure of 4/25 (0.16) as much as the initial moment, or decreased BY a factor of 25/4 (6.25). Good luck!
5/2 = 2.5
3 revs. Geme' 10 points!
2.5
3.3679
9.26