Verified answer

c) 90m

The average speed is 15 m/s times the time 6s = 90 meters.

Eds

Do you have the equations for motion with constant acceleration?

I'm sure someone here has probably already cranked out the math for you, but if you are in physics, these are very basic.

There are 3 or 4 equations using distance, velocity, acceleration, and time.

The equation you need for this one is

x=x init + 1/2( Vinit + Vx) * t

since x init and Vinit are zero from the problem statement, this becomes quite simple to solve.

If you are given 2 or 3 of the variables, distance, velocity, acceleration, or time, all you have to do is choose the equation with one unknown. Occasionally, you may be given some where you have to solve 2 sets of equations with 2 unknowns but if you are struggling with this one, you will really have a hard time with those.

Good luck

distance = 1/2 acceleration X ( time to the second power)

d=1/2 at^2

acceleration = change in velocity / change in time

a=(30-0)/(6-0) =5 m/s/s

distance = .5 X 5 X6^2=90 m

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(c) 90

Acceleration = a = 30m/s / 6s = 5 m/s^2

x(t) = 0.5*a*t^2

x(t) = 0.5*5*6^2=90m

c

c

(c) 90m