A 70 kg person is standing in an elevator when the elevator begins accelerating upwards at a rate of 1.5 ��/��ଶ. With what force does the elevator floor exert on the woman’s feet? . Created by hannah. science-mathematics-en - physics-en

For these elevator problems, F = m*(g ± a)+ if accelerating upward, - if accelerating downwardso here, F = 70kg * (9.8 + 1.5)m/s² = 791 N ≈ 790 N