A 1150-kg car traveling in a straight line at 126.0 km/hr runs into a 1750-kg car traveling in the same direction at 72.90 km/hr. If the two vehicles stick together, what is the velocity (in magnitude and direction) of the combination?
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Verified answer
I = I1+I2 = 1150*126/3.6+1750*72.90/3.6 = 75,687.5 Nsec
Vx = I/(m1+m2) = 75,687.5/2900 = 26.10 m/sec (93.96 km/h)
Momentum is conserved.
m1v1 + m2v2 = (m1 + m2)v3
You know everything except v3.