x^3 - x + 3x^2y + 3xy^2 + y^3 - y
= x^3 + y^3 + 3xy(x+y) - (x+y)
= (x+y)(x^2 - xy+ y^2) + 3xy(x+y) - (x+y)
= (x+y)(x^2 - xy+ y^2 + 3xy - 1)
=(x+y)( x^2 + 2xy+ y^2 -1)
= (x+y)[(x+y)^2 - 1]
=(x+y)(x+y + 1)(x+y -1)
=(x^3 + 3x^2y + 3xy^2 + y^3) - (x+y)
=(x+y)^3 - (x+y)
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Verified answer
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
= x^3 + y^3 + 3xy(x+y) - (x+y)
= (x+y)(x^2 - xy+ y^2) + 3xy(x+y) - (x+y)
= (x+y)(x^2 - xy+ y^2 + 3xy - 1)
=(x+y)( x^2 + 2xy+ y^2 -1)
= (x+y)[(x+y)^2 - 1]
=(x+y)(x+y + 1)(x+y -1)
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
=(x^3 + 3x^2y + 3xy^2 + y^3) - (x+y)
=(x+y)^3 - (x+y)
= (x+y)[(x+y)^2 - 1]
=(x+y)(x+y + 1)(x+y -1)