N2(g)+3H2(g)--> 2NH3(g)?

Nitrogen and hydrogen combine at high temperature, in the presence of a catalyst, to produce ammonia.

N2(g)+3H2(g) 2NH3(g)

Assume 0.140 mol of N2 and 0.450 mol of H2 are present initially.

After complete reaction, how many moles of ammonia are produce?

How many moles of H2 remain?

How many moles of N2 remain?

What is the limiting reactant? (hydrogen or nitrogen)

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