Verified answer

I think this is an acid and it's conjugate base! so you'd use the equation

pH = pKa + log(base/acid)

So you have the pH, pKa is just -log of your Ka which is also given.. and you also have your base, which leaves you to do the math to find your acid! :)

PH=-log[H+] U shud understand what log stands for. log(subscript10)X=a, is equivalent to asserting 10^a=x; Now we could do a) [H+]=0.a million=10^(-a million) using log on the two factors, we get, log[H+]=log[10^(-a million)] using the reality that, log(a^b)=b*log(a) , it follows that, log[H+]=-1log[10] multiplying the two factors with -a million, and applying log[10]=a million, -log[H+]=a million*a million=a million in addition, b)0.01=10^-2 ph=2 c)ph=3 d)ph=5 e)ph=4 Do u see a trend? i'm hoping u do, ans is the unfavourable of the skill to which the ten shud be raised to show the given hydrogen ion concentration. applying a calculator, first discover the log( base 10), of despite the concentration of Hydrogen ion is and multiply the ans with the aid of -a million, and thats the PH.