A chair of weight 120 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F= 42.0 N directed at an angle of 39.0 degrees below the horizontal and the chair slides along the floor.
A) Using Newton's laws, calculate , the magnitude of the normal force that the floor exerts on the chair. Express your answer in newtons.
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Verified answer
For this, you have to find the vertical component of the pushing force, then add it up with the weight of the chair.
Knowns:
Weight = w = 120 N
y component of the F = 42.0xsin39 work, work that out with calculator.
Solution:
Normal = w + Fy = 120 + 42.0xsin39.
Good luck.