Fluorine gas can react with ammonia gas to produce dinitrogen tetrafluoride gas and hydrogen fluoride gas. This reaction is described by the following balanced equation:
5 F2 (g) + 2 NH3 (g) N2F4 (g) + 6 HF (g)
What mass of hydrogen fluoride gas is produced from 135 g of ammonia gas assuming that there is an ample amount of fluorine gas present for the reaction to be completed?
A. 405 g
B. 38.3 g
C. 476 g
D. 52.9 g
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Verified answer
from bal. rxn., 6 moles of HF is produced from 2 moles of NH3 (3:1)
moles NH3= 135 g NH3/ 17 g/mole NH3= 7.94
7.94 moles NH3 x 3 x molec. wt. HF = ans.