3H2(g)+N2(g) --> 2NH3(g)?
How many grams of NH3 can be produced from 4.42mol of N2?
How many grams of H2 are needed to produce 14.21g of NH3?
How many molecules (not moles) of NH3 are produced from 6.87×10−4g of H2?
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Verified answer
1) mole ratio
N2 to NH3 = 1:2
(4.42 x 2 mol) x 17.0g NH3/mol = 150g (150.3g to be specific)
2) Mole ratio H2 to NH3 is 3:2
14.21g x 1 mol NH3/ 17.03g = 0.8344 moles NH3
0.8344 mol NH3 x (3 H2/ 2 NH3) x (2.016g H2/ mol) = 2.523g H2
3) 6.87x10^-4g H2 x 1 mol H2/ 2.02g = 3.40 x 10^-4 mol H2
Mole ratio H2 to NH3 is 3:2 & 1 mole = 6.02 x 10^23 molecules
Molecules NH3 = 3.40 x 10^-4 mol H2 x (2 NH3/ 3 H2) x (6.02x10^23 molecules/ 1 mol) =
1.36 x 10^20 molecules NH3 produced