(look at pic below)What is the net displacement and total distance traveled in the first 12s of this graph? the answers is 19m and 29m respectively but I have no idea how to do it. I tried taking the area below the graph but its too much. How do you do it? please be specific. thanks
http://i1359.photobucket.com/albums/q782/urfavpers...
Update:please give help that is specified to this problem.
Copyright © 2024 VQUIX.COM - All rights reserved.
Answers & Comments
Verified answer
Take the average Acceleration for 12 seconds and then for total seconds. Then apply the following:
Displacment = A x T^2 / 2