Verified answer

Prepare an ICE chart following the concentrations of each species during the reaction.

Molarity . . . . . .SCl2(g) + 2 C2H4(g) <=> S(CH2CH2Cl)2(g)

Initial . . . . . . . .0.459 . . . . 0.919 . . . . . .. . . . . .0

Change . . . . . . .-x . . . . . . .-2x . . . . . . . . . . . . x

Equilibrium . . .0.459-x . . .0.919-2x . . . . . . . . . .x

But we are told that at equilibrium, [S(CH2CH2Cl)2] = 0.141 M = x

[SCl2] = 0.459 - x = 0.459 - 0.141 = 0.318 M

[C2H4] = 0.919 - 2x = 0.919 - (2)(0.141) = 0.637 M

Kc = [S(CH2CH2Cl)2] / [SCl2][C2H4]^2 = (0.141) / (0.318)(0.637)^2 = 1.09

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