What is the pH of a solution that contains 0.50M sodium benzoate and 0.75M benzoic acid (Ka= 6.8 x 10^-5)
thanks!
It is a buffer solution.
we can use the equation
pH = pKa + log [ sodium benzoate ] / [ benzoic acid ]
pKa = - log Ka = 4.17
pH = 4.14 + log 0.50 / 0.75 = 3.96
use the concept of buffer solution
here it's an acidic buffer
An acidic buffer solution is simply one which has a pH less than 7. Acidic buffer solutions are commonly made from a weak acid and one of its salts - often a sodium salt.
pH=pKa+log[salt ]/[acid]
pH=3.99
for more help follow this link
http://en.wikipedia.org/wiki/Henderson-Hasselbalch...
and also read the buffer concept
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Verified answer
It is a buffer solution.
we can use the equation
pH = pKa + log [ sodium benzoate ] / [ benzoic acid ]
pKa = - log Ka = 4.17
pH = 4.14 + log 0.50 / 0.75 = 3.96
use the concept of buffer solution
here it's an acidic buffer
An acidic buffer solution is simply one which has a pH less than 7. Acidic buffer solutions are commonly made from a weak acid and one of its salts - often a sodium salt.
pH=pKa+log[salt ]/[acid]
pH=3.99
for more help follow this link
http://en.wikipedia.org/wiki/Henderson-Hasselbalch...
and also read the buffer concept