Okay, I'm going to try and explain this as best as I can.
Part A
Since you're reacting 55.7 grams of that substance, you need to find out how many grams of NH3 will cancel it out. Factor label
55.7 g 1 mole 2 mol NH3
____ x __________________ x ____________
1 (however many grams of that in a mole) 1 mole K2...
^crap, that's not coming out as it should...but I hope you get it. Stupid formatting.
and then find moles to grams of NH3 the same way. I hope that makes sense.
Part B
This is done is almost the same way as Part A, factor label 55.7 grams into moles, mole ratio, and then moles into grams of cisplatin. Only, you won't end up with all of that, just 98%. Multiply the answer you got by .98.
Answers & Comments
Verified answer
Okay, I'm going to try and explain this as best as I can.
Part A
Since you're reacting 55.7 grams of that substance, you need to find out how many grams of NH3 will cancel it out. Factor label
55.7 g 1 mole 2 mol NH3
____ x __________________ x ____________
1 (however many grams of that in a mole) 1 mole K2...
^crap, that's not coming out as it should...but I hope you get it. Stupid formatting.
and then find moles to grams of NH3 the same way. I hope that makes sense.
Part B
This is done is almost the same way as Part A, factor label 55.7 grams into moles, mole ratio, and then moles into grams of cisplatin. Only, you won't end up with all of that, just 98%. Multiply the answer you got by .98.
I hope I didn't confuse you!