A 90.0kg person rides a spinning amusement park ride that has a radius of 11.5 m. If the person's tangential speed is 13.2 m/s, what is the magnitude of the centripetal force acting on the person?
m*v^2/r
90*13.2^2/11.5
1364 N
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Spinning Amusement Park Ride
Your working formula is
F = mV^2/r
where
F = force
m = mass of the person
V = velocity
r = radius
Substituting values,
F = (90)(13.2)^2/11.5
F = 1363.62 N
cheating is unscrupulous and wrong. I recommend you quit/
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Verified answer
m*v^2/r
90*13.2^2/11.5
1364 N
_________________-
Spinning Amusement Park Ride
Your working formula is
F = mV^2/r
where
F = force
m = mass of the person
V = velocity
r = radius
Substituting values,
F = (90)(13.2)^2/11.5
F = 1363.62 N
cheating is unscrupulous and wrong. I recommend you quit/