physics?!?
A 2600 kg car traveling north is slowed down uniformly from an initial velocity of 26.7 m/s by a 7950 N braking force acting opposite the car's motion.
What is the car's velocity after 1.92 seconds? Answer in m/s.
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Verified answer
using F=m*a
7950=2600*a
solve for a
a=3.06
Plug that into the equations of motion
v(1.92)=26.7-3.06*1.92
20.82 m/s
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