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Calculate the magnitude of the force between two 3.85 µC point charges 7.8 cm apart.
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Calculate the magnitude of the force between two 3.85 µC point charges 7.8 cm apart.
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By coulombs law in Electrostatics,
F = (1/(4*pi*epsilon0))*(q1*q2/r^2);
F = 9*10^9 * (3.85*10^-6)^2/(7.8*10^-2)^2
F= 21.93 Newton.
its easy question just use coloumb law F= kQq/r2 justb substute k=9000000000 Q= 0.00000385
q= 0.000000385 r= 0.078
and take square of r