If the earth was at one half of its present distance from the sun and had the same orbital speed, the
number of days in one year would be approximately.
a. 730 b. 182 c. 365 d. 129
please sole the numerical
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Verified answer
T = C/v = 2piR/v is the time around at R orbit. And t = c/v = 2piR/2v is the time around at the same v when r = R/2 the radius is 1/2 R.
We compare: T/t = 2piR/v//piR/v = 2; so t = T/2 and the time around one cycle at r = R/2 is 1/2 the time at R; i.e., 1/2 year. That's roughly 182 days. ANS. b.
C