Physics - Escape velocity?
The escape velocity of a bullet from the surface of planet Y is 1599 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.45 times that of Y, and its radius is 0.823 times the radius of Y.
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Isn't the escape velocity = Ve = √gR ?
where g = GM/R² so Ve = √(GM/R²)(R) = √GM/R
which means the Ve is proportional to
√M/R = √1.45/0.823 = √1.76185 = 1.33 (Ve of Y) = (1.33)(1599) ≈ 2100 m/s ANS
The escape speed of a black hollow is c. there isn't any such element as a black hollow with an escape speed of 100c. The horizon of an 100c escape speed may well be interior of an journey horizon of c, and no suggestions from the 100c horizon can get to the Universe outdoors the c horizon; ergo, who cares? in case you define the mass of the black hollow then v? = ?(2GM/r), and why take a wild wager at ".999999c or something". An M? black hollow has an escape speed of 0.0014c from a million miles away. Me thinks you over estimate the capacities of a black hollow. you're additionally forgetting that resultant velocities are not purely the sum of the guy velocities. Relativity do no longer play that, Homey. .