Ta có :
x³- 4x²+ x+ 6 = 0
x³ + x² - 5x² - 5x + 6x + 6 =0
x²(x + 1) -5x(x + 1) +6(x + 1) =0
(x + 1)(x² -5x +6 ) =0
(x + 1)(x² -2x -3x +6) =0
(x + 1)[x(x - 2) -3(x - 2)] =0
(x + 1)(x - 2)(x - 3) = 0
Suy ra x = -1
hoặc x = 2 ; x = 3
bấm máy tính cũng đc mà.:)
<=>(x+1)(x^2 -5x +6)=0
<=>(x+1)(x-2)(x-3) =0
=> x=-1,x=2,x=3
Copyright © 2024 VQUIX.COM - All rights reserved.
Answers & Comments
Verified answer
Ta có :
x³- 4x²+ x+ 6 = 0
x³ + x² - 5x² - 5x + 6x + 6 =0
x²(x + 1) -5x(x + 1) +6(x + 1) =0
(x + 1)(x² -5x +6 ) =0
(x + 1)(x² -2x -3x +6) =0
(x + 1)[x(x - 2) -3(x - 2)] =0
(x + 1)(x - 2)(x - 3) = 0
Suy ra x = -1
hoặc x = 2 ; x = 3
bấm máy tính cũng đc mà.:)
<=>(x+1)(x^2 -5x +6)=0
<=>(x+1)(x-2)(x-3) =0
=> x=-1,x=2,x=3