2C3H6(g) + 2NH3(g) + 3O2(g) 2C3H3N(l) + 6H2O(g)?
2C3H6(g) + 2NH3(g) + 3O2(g) 2C3H3N(l) + 6H2O(g)
Determine how many kg of acrylonitrile can be prepared from 1490 kg of propene, 692 kg of ammonia, and 3970 kg of oxygen.
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Moles propene = 1490000 / 30 g/mol =49667
Moles ammonia = 692000 / 17 g/mol = 40706
Moles O2 = 3970000 g/ 32 g/mol = 124062
NH3 is the limiting reactant
we get 40706 moles of C3H3N
mass = 40706 mol x 53 g/mol = 2157418 g => 2157 Kg